Question

Find the distance between the two given points.3,1 (-1,-2)

Answer 1

Answer:

d= (y2 – yı)2 + (x2 – ¤1)²

d= (2-1)2+(-1 - 3)²

d = v1+ 16

d= V17

Here's a fun little tidbit to link concepts, as well:

Let (x1, Y1) and (x2, Y2) be distinct points in a Cartesian plane. For simplicity, let X1 = 0 and Y2 = 0.

This simplifies the formula such that:

d = Vy? + x2

d? = y? + x?

This is the Pythagorean Theorem. The distance formula, rather, accounts for the change of vertical or horizontal position instead of assuming that the triangle lies on the axes.

So, just imagine the points as two points of a triangle, find its rise & run, then use these to find the triangle's

hypotenuse.

Answer 2

Answer:

d = 5

Step-by-step explanation:

For:

(X1, Y1) = (3, 1)

(X2, Y2) = (-1, -2)

Distance Equation Solution:

d=√(−1−3)²+(−2−1)²

d=√(−4)²+(−3)²

d=√16+9

d=√25

d=5