Find the distance between two points (0,-1,1)(3,3,13)
Answers
Answered by
1
x1 = 0 , y1 = -1 , z1 = 1
x2 = 3 , y2 = 3 , z2 = 13
DISTANCE
= √ ( x2 - x1 )² + ( y2 - y1 )² + ( z2 - z1 )²
= √ ( 3 - 0 )² + ( 3 - (-1 ) )² + ( 13 - 1 )²
= √ 3² + 4² + 12²
= √ 9 + 16 + 144
= √ 169
= 13
x2 = 3 , y2 = 3 , z2 = 13
DISTANCE
= √ ( x2 - x1 )² + ( y2 - y1 )² + ( z2 - z1 )²
= √ ( 3 - 0 )² + ( 3 - (-1 ) )² + ( 13 - 1 )²
= √ 3² + 4² + 12²
= √ 9 + 16 + 144
= √ 169
= 13
Physicist182:
MARK ME BRAINLIEST IF MY ANSWER IS CORRECT.
great bro
Answered by
1
So to 0 to -1, distance is 1, 1 to 3 the distance is 2, 3 to 13 is 10. I hope it will help you
well try
Similar questions