Question

verify that :-

1 and 2 are the zeros of the polynomial p(x) = (x - 1) (x - 2).
Please answer me fast!!!!!!! guys....

Answer 1

Hey mate !!

Here's your answer !!

1 and 2 are zeros of polynomial means that if the value is substituted for x then the equation turns zero.

So let's prove using x = 1 first

$= (x - 1)(x - 2) \\ = (1 - 1)(1 - 2) \\ = (0)( - 1) \\ = 0$
Since the equation turns to be zero, 1 is the zero of the polynomial.

Now let's take x = 2
$= (x - 1)(x - 2) \\ = (2 - 1)(2 - 2) \\ = (1)(0) \\ = 0$
Since the equation turns to be zero, 2 is also the zero of the polynomial.

Hence Verified !!

Hope it helps !!

Cheers !!

Answer 2

p(x) = (x-1)(x-2)
p(x) = x square -2x - x +2
p(x) = x square- 3x + 2

zeros of the x=1;2

then put in the value of x in equation

p(1) = 1 - 3+2 =0
p(2)= 4 -6+2 = 0

p(2) = p(1) = 0

hence proove that