find the distance between two possible positions of a real object in front of a convex lens of focal length 20 cm such that the size of image is triple the size of object
50/3 cm
40/3cm
80/3cm
40cm
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Given: Convex lens of focal length 20 cm.
To find: The distance between two possible positions of a real object
Solution:
- Now we have given convex lens of focal length 20 cm such that the size of image is triple the size of object.
- So magnification of the lens = - 3 ( real object)
- So the magnification of lens is given as = f/f+u = m
- Let u = - u1
- So putting the values in it, we get:
-3 = 20/ 20-u1
-60 + 3u1 = 20
u1 = 80/3 cm
Answer:
The distance between the position of a real object is 80/3 cm
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