how to solve this (x3 +y3+z3)2
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Answer: Step-by-step explanation: x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx). If x + y + z = 0, then x3 + y3 + z3 – 3xyz = 0 or x3 + y3 + z3 = 3xyz.
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Multiply each of them with the number out of the bracket.
ANSWER
2x³+2y³+2z³
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