find the distance bywn (-2,-3),(3,2)
pls ans fast very urgent
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Answered by
0
Using distance formula distance will be √(x1-x2)^2+(y2-y1)^2
On substituting the values we get
Distance between [-2,-3],(3,2)=5√2 units
On substituting the values we get
Distance between [-2,-3],(3,2)=5√2 units
Answered by
1
Hi ,
we know that ,
distance between distance between two
points ( x1 , y1 ) and ( x2 , y2 ) is
√ ( x2 - x1 )² + ( y2 - y1 )²
according to the problem given ,
( x1 , y1 ) =A ( -2 , -3 )
( x2 , y2 ) = B( 3 , 2 )
distance = √ ( x2 - x1 )² + ( y2 - y1 )²
AB = √ [ 3 - ( -2) ]² + [ 2 - ( -3 ) ]²
= √ ( 3 + 2 )² + ( 2 + 3 )²
= √ 5² + 5²
= √ 25 + 25
= √ 50
= √ ( 5 × 5 ) × 2
= 5√2
therefore ,
AB = 5√2
I hope this helps you.
:)
we know that ,
distance between distance between two
points ( x1 , y1 ) and ( x2 , y2 ) is
√ ( x2 - x1 )² + ( y2 - y1 )²
according to the problem given ,
( x1 , y1 ) =A ( -2 , -3 )
( x2 , y2 ) = B( 3 , 2 )
distance = √ ( x2 - x1 )² + ( y2 - y1 )²
AB = √ [ 3 - ( -2) ]² + [ 2 - ( -3 ) ]²
= √ ( 3 + 2 )² + ( 2 + 3 )²
= √ 5² + 5²
= √ 25 + 25
= √ 50
= √ ( 5 × 5 ) × 2
= 5√2
therefore ,
AB = 5√2
I hope this helps you.
:)
Anonymous:
thanx for ur ans frnd
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