find the distance coverd by a particle during the time interval of 0 and 10 sec.
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Answer:
50m
Explanation:
Change of speed =10m/s
time= 10 s
Therefore ,acceleration = change in velocity/ time= 10/10 = 1
By using Newton's equation of motion s=ut+1/2at^2
s= (0)10 + 1/2 (1)(10)^2
s= 0 + 50
s= 50
Distance covered is 50m
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