Question

Find the distance covered by a body when it's initial velocity is 2m/s and then it come to rest in 8s at an an acceleration of - 4m/s

Answer 1

Answer:

s=ut+1/2×at×at

s=2×0.8+1/2×4×(0.8)(0.8)

s=1.6+1.28

s=2.88m.

Explanation:

From the formula [s=ut+1/2×at×at],

we can find the distance.