Find the distance from point S(1,1,3) to the plane 3x + 2y +6z = 6
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Answer:
23/7
Step-by-step explanation:
d= 3(1)+2(1)+6(3)
\sqrt{9 + 4 + 36}9+4+36
d= 3+2+18
\sqrt{49}49
d = 23/7
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