Math, asked by siri3257, 1 year ago

Find the distance from s(1,1,3) to the plane 3x+2y+6z=0

Answers

Answered by rahman786khalilu
0

d= 3(1)+2(1)+6(3)

 \sqrt{9 + 4 + 36}

d= 3+2+18

 \sqrt{49}

d = 23/7

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