find the distance from the eye at which a coin of 2cm diameter should be held to hide the sun whose angular diameter is 31'
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i dont know
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Let the angles of the triangle be (a−d)°, (a)° and (a+d)°.
We know:
a−d+a+a+d=180⇒3a=180⇒a=60
Given:Number of degrees in the least angleNumber of degrees in the mean angle=1120or, a−da=1120or, 60−d60=1120or, 60−d1=12or,120−2d=1or, 2d=119or, d= 59.5
Hence, the angles are (a−d)°, (a)° and (a+d)°, i.e., 0.5°, 60° and 119.5°.
∴ Angles of the triangle in radians = (0.5×π180), (60×π180) and (119.5×π180)
= π360, π3 and 239π360
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