Question

Find the distance from the line 4x =3y-5 to the point (3, - 1)

Answer 1

Answer:

The distance d between the line ax+by+c=0 and point (x

1

,y

1

) is given by

d=∣

a

2

+b

2

ax

1

+by

1

+c

∣

Therefore, Required distance=∣

4

2

+(−3)

2

4(2)−3(1)+5

∣=

5

10

=2