find the distance from the plane
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Heya!!!
Equation of plane is 6x -3y +2z = 4
Co-ordinates of point ( 2 , 5 , -3 )
_______________________________
Let the distance from given point to the given plane be = d
=>
d =
6 ( 2 ) - 3 ( 5 ) + 2 ( -3 ) - 4
___________________
√ ( 6² + 3² + 2² )
=>
d =
12 - 15 - 6 - 4
_________
√ 49
=>
d =
-13
__
7
=>
d = 13/7 units
Equation of plane is 6x -3y +2z = 4
Co-ordinates of point ( 2 , 5 , -3 )
_______________________________
Let the distance from given point to the given plane be = d
=>
d =
6 ( 2 ) - 3 ( 5 ) + 2 ( -3 ) - 4
___________________
√ ( 6² + 3² + 2² )
=>
d =
12 - 15 - 6 - 4
_________
√ 49
=>
d =
-13
__
7
=>
d = 13/7 units
anand5442:
Right..
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