Question

Find the distance of (1,-1) from 3x-4y + 8 = 0​

Answer 1

Answer:

2/5

Step-by-step explanation:

3×-4y+8=0 + 1 - 1

3×-4y= 1 - 1 - 8

3×-4y = -10

-12y + 30

-12y = 30

y = 30/ -12

y = 2/5

Answer 2

Answer:

The distance of (1,-1) from  3x-4y + 8 = 0​  is 3 units

Step-by-step explanation:  

Given problem

Find the distance of (1,-1) from  3x-4y + 8 = 0​

⇒ compare the given line 3x - 4y + 8 = 0​ with ax + by + c =0  

⇒ a = 3, b = -4 and c = 8

⇒ the formula for the distance of a line ax + by + c = 0  from a point (x₁, y₁) is     d = | ax +by+ c| / √(a² + b²)  

The distance of (1,-1) from  3x-4y + 8 = 0​  

      d = | 3(1) + (-4) (-1) + 8 | / √ [3² + (-4)²]      

         = | 3 + 4 +8 | /√ 9+16

         = 15/√25  

         = 15/5 = 3 units