Question

find the distance of a point p(x,y) from the original

Answer 1

Point from origin is (0,0)
and p=(x,y)
by applying distance formula
=√(x²-x¹)²+(y²-y¹)²
=√(x-0)²+(y-0)²
=√x²+y²
ans.

Answer 2

distance formula = √{ (x2-x1)^2+(y2-y1)^2 }
here one pt. is P ( x,y ) and second pt. is origin ( 0,0 )..
so, x1 = x , x2 = 0 ,y1 = y and y2 = 0...
by putting all values in eq. ..
answer is √{ x^2+y^2 }........

Hope you understand...
plz mark as brainlist..