Question

find the distance of image when an object is placed on the principal Axis at a distance of 10cm in front of a concave mirror whose radius of curvature is 8 centimetres ​

Answer 1

mirror formula is 1/f = 1/v + 1/u
since u =10cm (-) object distance is taken as negative
and you are given radius of curvature which is - 8 since the mirror is a concave mirror the radius of curvature will be negative
and focal length= radius /2
therefore f= -4 cm
and now use the mirror formula
as mentioned above
1/-4 = 1/v +1/-10
therefore v= 40/30 = 4/3 = 1.33

Answer 2

Answer:

Explanation:

U=-10cm

R=-8cm

F=r/2

F=-8/2

F=-4

1/f=1/u+1/v

1/v=1/f-1/u

1/v=1/-4+1/10

1/v=10-4/-40

1/v=6/-40

V=-40/6

V=-6.67