Find the distance of Line x + 2 by 3 is equal to Y + 1 by 2 is equal to Z minus 3 by 2 at distance 3 root 2 from point One, two, three
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Given line is x-y=5 and point (-2,3).We want distance between P(-2,3) and line L : x-y=5.
Equation of line parallel to L and passing through P is
M :x-y=-5.
Required distance =|OL-OM|
=|5/√(2)-(-5/√(2))|
=10/√(2)
=5√(2)
Formula used length of perpendicular drawn from origin (0,0) to line ax+by+c=0 is
=c/√((a)^2+(b)^2).
Equation of line parallel to L and passing through P is
M :x-y=-5.
Required distance =|OL-OM|
=|5/√(2)-(-5/√(2))|
=10/√(2)
=5√(2)
Formula used length of perpendicular drawn from origin (0,0) to line ax+by+c=0 is
=c/√((a)^2+(b)^2).
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