Question

find the distance of point (3 -5) from the line 3x-4y-26=0​

Answer 1

Answer:

Step-by-step explanation:

Given,

Point(D) = ( 3 , - 5)

Line = 3x - 4y - 26 = 0

To Find :-

Distance b/w them

Solution :-

Comparing " 3x - 4y - 26 = 0" with general equation " Ax+by+C = 0" :-

We can say that :-

A = 3 ,B = - 4 , C = - 26

Let, D(3 , -5) = (x , y)

Distance Formula :-

$d=\dfrac{|Ax+By+C|}{\sqrt{A^2+B^2}}$

$=\dfrac{|3(3)-4(-5)-26|}{\sqrt{(3)^2+(-4)^2}}$

$=\dfrac{|9+20-26|}{\sqrt{25}}$

$=\dfrac{|3|}{5}$

$=\dfrac{3}{5}$