Question

find the distance of point (4 -5) from y axis

Answer 1

Answer:

The distance of the point (4,-5) from the y-axis is 4 units.

Step-by-step explanation:

If a point is defined as (x,y), then the distance between y-axis and the point (x,y) is |x| and the distance between x-axis and the point (x,y) is |y|.

The given point is (4,-5).

This point is 4 units left from the y-axis and 5 units below the x-axis.

It means the distance between y-axis and the point (4,-5) is 4 and the distance between x-axis and the point (4,-5) is 5.

Therefore distance of the point (4,-5) from the y-axis is 4 units.

Answer 2

Answer:

Distance of the point (-5,4) from x-axis means distance of the point (-5,4) from (-5,0).

Therefore, the required distance =(−5+5)2+(4−0)2=16=4