Question

find the distance of the image when an object is placed at a distance of 10 cm in front of a concave mirror whose radius of curvature is 8 cm.​

Answer 1

Given:-

Object placed at a distance = 10 cm

The mirror is Concave Mirror

The Radius of Curvature = 8cm

To Find :-

The Image Location.

Solution:-

We are given with a concave Mirror whoose Radius of curvature = 8 cm.

Since, Radius of Curvature = 8cm

Focal lenght of the mirror = 1/2*R = 1/2*8 = 4 cm

The Image Position =?

Now,

We know that,

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v} \\ \\ \frac{1}{ - 4} = \frac{1}{ - 10} + \frac{1}{v} \\ \\ \frac{1}{v} = \frac { - 1}{10} \times - \frac{2}{10} = \frac{20}{3}$

Hence 20/3 is the Image distance...