find the distance of the image, when as object is placed on the principal axis at a distance of 10 cm in front of a concave mirror whose radius of curvature is -8 cm
Ashritha111:
hmmm
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Answered by
7
hey mate here is ur ans
u = distance of object= - 10 cm
R = radius of curvature = -8
so we know that f= R/2
f= -8/2
= -4
v= distance of image
we know the formula
1/f= 1/v- 1/u
1/-4= 1/v- 1/-10
1/v= -1/10-1/4
1/v= -2-5/20
1/v= -7/20
v= -20/7
v = - 2.8
hope it help u
u = distance of object= - 10 cm
R = radius of curvature = -8
so we know that f= R/2
f= -8/2
= -4
v= distance of image
we know the formula
1/f= 1/v- 1/u
1/-4= 1/v- 1/-10
1/v= -1/10-1/4
1/v= -2-5/20
1/v= -7/20
v= -20/7
v = - 2.8
hope it help u
Answered by
12
please mark it brainleist
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