Question

find the distance of the point (-1, 1) from the line 12(x+6) = 5(y-2)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

The given equation of the line is 12(x+6)=5(y−2).

12x+72=5y−10

12x−5y+82=0

On comparing this equation with general equation of line Ax+By+C=0, we get,

A=12,B=−5,C=82

We know, perpendicular distance (d) of a line Ax+By+C=0 from a point (x1,y1) is given by

d=A2+B2

Ax1+By1+C∣

Therefore, the distance of the point (−1,1) from given line is :

=(12)2+(−5)2

12(−1)+(−5)(1)+82∣=1365=5 units