Find the distance of the point (−2, 5, −7) from the −
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Answer:
Step-by-step explanation:
r
.(6
i
^
−3
j
^
+2
k
^
)=4⇒(x
i
^
+y
j
^
+z
k
^
).(6
i
^
−3
j
^
+2
k
^
)=4
⇒6x−3y+2z=4
Distance of given point from the plane 6x−3y+2z−4=0
=
∣
∣
∣
∣
∣
6
2
+3
2
+2
2
6(2)−3(5)+2(−3)−4
∣
∣
∣
∣
∣
=
7
13
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