find the distance of the point - 3, - 2 from the x-axis
Answers
Answered by
1
Answer:
√13
Step-by-step explanation:
distance of point -3,-2 from origin ie. 0,0
x1=-3, x2=0 & y1=-2,y2=0
by distance formula
distance =√(x1-x2)^2+)y1-y2)^2
=√(-3-0)^2+(-2-0)^2
=√(-3)^2+(-2)^2
=√9+4
=√13
Answered by
0
Answer:
1
Step-by-step explanation:
Let,A=-3,B=-2
d(AB)=√(x2-x1)²+(y2-y1)²
=√[-2-(-3)]²
=√(-2+3)²
=√(1)²
=1
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