Question

find the distance of the point P(-4,3,5) from the coordinate axes.
plz answer asap

Answer 1

Answer:

From x-axis: $\sqrt{34}units$

From y-axis: $\sqrt{41}units$

From z-axis: 5 units

Step-by-step explanation:

Given the point P(-4,3,5).

we have to find the distance from the coordinate axis.

The perpendicular distance from the coordinate axes can be calculated using Pythagoras theorem which can be calculated as

Distance of P from the x-axis is

$\sqrt{3^2+5^2}=\sqrt{9+25}=\sqrt{34}$

Distance of P from the y-axis is

$\sqrt{(-4)^2+5^2}=\sqrt{16+25}=\sqrt{41}$

Distance of P from the z-axis is

$\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5$