find the distance travelled by an object if it's initial velocity is 5mps , acceleration is 1.2mps^2 and the total time it is moving is 20 sec. also find out its final velocity
Answers
Question :
Find the distance travelled by an object if it's initial velocity is 5m/s , acceleration is 1.2m/sec² and the total time it is moving is 20 sec.also find out its final velocity.
Kinematic equations for uniformly accelerated motion .
and
Solution :
we have ,initial Velocity , u=5m/s
a= 1.2m/sec²
t = 20sec
By using equation of motion
Now , By equation of motion
Therefore,The distance travelled by an object is 340 m and it's final velocity is 29m/s .
An object moves for 20 seconds with an initial velocity (u) of 5 m/s with an acceleration (a) of 1.2 m/s².
We are supposed to calculate the distance travelled by the object and also the final velocity (v).
We can use the equation of motion and calculate the required quantities.
Let's find the final velocity (v) :
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Now,we can use the value of v in 3rd equation of motion and find the distance travelled by the object.
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•°• Distance travelled by the object with Initial velocity of 5 m/s, final velocity of 29 m/s and with an acceleration (a) of 1.2 m/s² is 340 m.