Question

Q4. If p(x) = 6x^3 + 5x^2- 3x + 2 find p(-1 )​

Answer 1

Answer:

4

Step-by-step explanation:

$p( - 1) = 6 {( - 1)}^{3} + 5 {( - 1)}^{2} - 3 \times ( - 1) + 2 \\ = > p( - 1) = 6 \times ( - 1) + 5 \times 1 + 3 + 2 \\ = > p( - 1) = - 6 + 5 + 5 \\ = > p( - 1) = 10 - 6 \\ = > p( - 1) = 4$