Math, asked by siddhant11996, 2 months ago

Find the domain &range of the real function f defined by
f(x) =  \frac{1}{ \sqrt{9 -  {x}^{2} } }

Answers

Answered by Anonymous
3

Domain and range

f(x)=

9−x

2

y=

9−x

2

9−x

2

≥0

9−x

2

≥0

x

2

≤9

x≤

+

3

x∈[−3,3]

y

2

=9−x

2

x

2

=9−y

2

x=

9−y

2

9−y

2

≥0

y

2

≤9y∈3,−3

y=+ve

∵y∈[0,3]

.

.

.

here is your answer

Answered by captainmarvel63
2

Answer:

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