Math, asked by reenajain840, 1 day ago

find the domain and range of 4/sqrt 9-16x2

Answers

Answered by bharatyelmar34
0

Answer:

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Answered by iyervinayak01
0
Domain-> 9-16x^2>=0 so x^2>=9/16
So x>=3/4 and x>=-3/4
Also 9-16x^2 is not equal to zero so
x is not equal to +3/4 and -3/4
So domain value of x is:
x belongs to (-3/4,3/4)union(3/4,infinity)
Now Range of y is:
y belongs to (-3/4,3/4)
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