Find the domain and range of
f(x)=1/√x-[x]
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Answer:
Step-by-step explanation:
Y= 1/√|x|-x
For the term inside the root to be positive it is required that √|x|- x is greater than or equal to zero. That is,
|x| - x >= 0
But here the term can't be zero as it is in the denominator. So,
|x| - x > 0
So |x| >x
This is possible only if x is a negative number. Therefore the domain of x will be the set of negative real numbers, i.e. (-infinity, 0).
Hope this will clear your doubt.
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