Find the domain and range of f(x)= 3/x-3
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Explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
solve 3−x=0⇒x=3←excluded value
⇒domain x∈R,x≠3
x∈(−∞,3)∪(3,∞)←in interval notation
f(x)=3+x3−x
divide terms on numerator/denominator by x
f(x)=3x+xx3x−xx=3x+13x−1
as x→±∞,f(x)→0+10−1=−1←excluded value
⇒range y∈R,y≠−1
y∈(−∞,−1)∪(−1,∞)
graph{(3+x)/(3-x) [-10, 10, -5, 5]}
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