Question

find the domain and range of f(x)=-|x| and √9-x2​

Answer 1

Answer:

If f(x) =

$\sqrt{9 - x { }^{2} }$

Step-by-step explanation:

Then

$9 \: - {x}^{2} \geqslant 0$

$(3 - \times )(3 + x) \geqslant 0$

$(x - 3)(x + 3) \leqslant 0$

Therefore x belongs to [-3,3]

And the domain of f is [-3,3]

The range of f is f belongs [0,3]

Hope this will help you.....