Question

Please solve it................. ​

Answer 1

Hope this helps!

6)

$( { - 8})^{10}$

7)

${8}^{(m + 5)} = 1 \\ {8}^{( - 5 + 5)} = 1 \\ since \: {a}^{0} = 1 \\ {8}^{0} = 1 \\ m = - 5$

9)

${ (\frac{5}{6} )}^{4}$

10)

$7 {x}^{0} - 3 \\ 7(1) - 3 \\ 7 - 3 \\ = 4$

14)

${ (\frac{7}{5}) }^{5} \times { (\frac{7}{5}) }^{7} = { (\frac{7}{5}) }^{12} \\ using \: exponent \: formula \: if \: bases \: are \: equal \: we \: can \: add \: the \: powers... \\ 5 + 7 = 12$

15)

${9}^{2} × {9}^{5} = ({3}^{2})^{7}$

17)

$\frac{9 \times 9}{3 \times 3 \times 3} \\ \frac{3}{1} \\ = 3 \\ therefore \: {3}^{1} = \frac{ {9}^{2} }{ {3}^{3} } \\ {3}^{1} = 3$

20)

${5}^{(6x + 6)} = 1 \\ {5}^{(6x + 6)} = {5}^{0} \\ (since \: {a}^{0} = 1) \\ as \: bases \: are \: equal...we \: can \: equate \: the \: powers \\ 6x + 6 = 0 \\ 6x = - 6 \\ x = - 1$

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