find the domain and range of
f(x) = x³-a³/x-a
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f(x)= (x−1)(3−x]
Now,
Under square root the polynomial must be positive. The domain is obtained by solving:-
(x−1)(3−x)≥0
You can obtain the zeroes of the polynomial
(x−1)(3−x)=0
If
x−1=0
x=1
If
3−x=0
⇒x=3
So,
x=1,3
So the polynomial is solved in the external intervals.
x>1,x>3
So,
x∈(1,+∞)
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