Question

Find the domain and the range
F(x) =2x+1

Answer 1

$\bf \LARGE \color{pink}{Hola! }$

GiveN :

$\mapsto \sf \: f(x) = 2x + 1$

SolutioN :

$\sf {\underline {Domain\:\: of \:\: function}} :$

$\sf \: We \: \: can \: \: put \: \: any \: \: value \: \: of \: \: x \: \: as \: \: it's \: \: a \: \: linear \: \: function$

$\therefore \: \sf \: domain \: \: is \: \: all \: \: real \: \: number \: \:$

Or we can say,

$\mapsto \sf \underline{\boxed {\sf{D_f \in R}}}$

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$\sf {\underline {Range\:\: of \:\: function}} :$

$\sf \: Substituting \: \: any \: \: real \: \: value \: \: of \: \: x \: \: we \: \: will \: \: get \: \: all \: \: real \: \: value \: \: as \: \: a \: \: output$

$\therefore \: \sf \: \: Range \: \: is \: \: all \: \: real \: \: number \: \:$

$\mapsto \sf \underline{\boxed {\sf{R_f \in R}}}$

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ConcepT BoosteR :

→ For better understanding we will look at the Graphical representation of the function.

[ Graph is attached in Photo ]

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HOPE THIS IS HELPFUL...