Question

Find the domain of 1/1-2sinx

Answer 1

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➖Function is f(x) = 1/(1 - 2sinx)
function is defined only when 1 - 2sinx ≠ 0


➖Let 1 - 2sinx = 0
sinx = 1/2 = sinπ/3


➖we know, if sinФ = sinα then, Ф = nπ + (+1)ⁿ α
so, x = nπ + (-1)ⁿπ/3 , where n is integers


➖Hence, domain of f(x) is all real number except {nπ + (-1)ⁿπ/3}


➖e.g., domain ∈ R - {nπ + (-1)ⁿπ/3 , n∈I}


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Answer 2

Answer:

Step-by-step explanation:

➖Function is f(x) = 1/(1 - 2sinx)

function is defined only when 1 - 2sinx ≠ 0

➖Let 1 - 2sinx = 0

sinx = 1/2 = sinπ/3

➖we know, if sinФ = sinα then, Ф = nπ + (+1)ⁿ α

so, x = nπ + (-1)ⁿπ/3 , where n is integers

➖Hence, domain of f(x) is all real number except {nπ + (-1)ⁿπ/3}

➖e.g., domain ∈ R - {nπ + (-1)ⁿπ/3 , n∈I}

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