Question

Find the domain of f(x) = x^2 - 4 *

all real numbers
all real numbers except 4
all real numbers except - 4
all real numbers except 2

Find the inverse of f(x) = x^2 - 4 *

y = ±√(x+4) y
= ±√(x-4) y
= ±√(x2)
no inverse function

Find the domain of the inverse function of f(x) = (x - 6) / (x + 9) *

All real numbers
All real numbers except 1
All real numbers except -1
No inverse function

Find the range of the inverse function of f
(x) = (x - 1) / (x - 3) *

All real numbers
All real numbers except 3
All real numbers except -3
No inverse function

Find the inverse function of f(x) = (5x - 12) / (x + 8)

f ^-1 (x)= (-8x-12)/(x-5)
f ^-1 (x)= (8x-12)/(x-5)
f ^-1 (x)= (8x-12)/(x+5)
f ^-1 (x)= (8x+12)/(x+5)​

Answer 1

Answer:

Answer:

The cost of cementing inside the tank is $6888.

Step-by-step explanation:

Given :

Length, breadth and depth (height) of the inside open safety tank are 6 m, 4 m and 7 m.

Rate of cementing is $42 per sq metre.

To find :

The cost of cementing inside the tank.

Solution :

[The shape of tank is cuboidal because it have length, breadth and height (or depth)]

We have to find cost of cementing inside the tank so, for this first we need surface area of inside of the open tank.

• Surface area of inside of the open tank = 2(lb + bh + lh) - lb

[Where, l is length, b is breadth and h is height or depth]

Put all values :

\implies⟹ Surface area = 2 × [(6 × 4) + (4 × 7) + (7 × 6)] - (6 × 4)

\implies⟹ Surface area = 2 × (24 + 28 + 42) - 24

\implies⟹ Surface area = (48 + 56 + 84) - 24

\implies⟹ Surface area = 188 - 24

\implies⟹ Surface area = 164

Thus,

Surface area of inside of the open tank is 164 m².

=> Cost of cementing 1 m² = $42

=> Cost of cementing 164 m² :

\implies⟹ 164 × 42

\implies⟹ 6888

Therefore,

The cost of cementing inside the tank is $6888.