Question

Find the domain of $\frac{x-1}{x+1}$ .

Answer 1

Answer:

I guess you were asking range.

Range is  R/{-1}.

Step-by-step explanation:

Let f(x)= $\frac{x-1}{x+1}$

if f(x) is real then $x+1\neq 0$

so, $x\neq -1$

Therefore range is  R/{-1}.