Math, asked by harshilchouhan9039, 7 months ago

find the domain of the function f(x)=square root 25-16x^2​

Answers

Answered by atharva7551s
3

Answer:

the main formula is integr U^p du = (1/1+p)U^p+1

let be U=(25 - 16x^2)^-1/2,

1/sqrt(25 - 16x^2) = (25 - 16x^2)^-1/2

du= -1/2)(-32x)(25 - 16x^2)^-1/2dx

integ du/-1/2)(-32x)= integ(25 - 16x^2)^-1/2dx

nteg du/16x)=1/16xu+c=integ(25 - 16x^2)^-1/2dx

finally

integ 1 / sqrt(25 - 16x^2) dx = 1/16xu+c= (1/16x)((25 - 16x^2)^-1/2) +c

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