Question

Find the dual of Y.X + X'+1 = 1​

Answer 1

Answer:

Explanation:

We know that,

x³-y³=(x-y)(x²+xy+y²)........................1

Given that,

x/y+y/x=-1

(x²+y²)/xy=-1

x²+y²=-xy

x²+y²+xy=0

(x²+xy+y²)=0

Multyplying by (x-y) on both sides we get,

(x-y)(x²+xy+y²)=(x-y)×0

By eq1 we get,

x³-y³=0

Hence x³-y³=0.

Answer 2

Answer:

The correct answer is Y+X . X'.1 = 0

Explanation:

Given,

Y.X + X'+1 = 1

To find the dual of the given expression,

We know that,  

.  ↔ And

+ ↔ Or

Here we need to replace

And (.) by Or (+)  &  Or (+) by And (.)  &  1 by 0

we get the solution,

Dual of Y.X + X'+1 = 1  is Y+X . X'.1 = 0

∦SPJ3