Question

find the edge of a cubical box if its volume is 110.592m³
please answer this question with full process​

Answer 1

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• A cubical box

• where volume is 110.592m³

${\sf{\green{\underline{\large{To\:find}}}}}$

• Edge of cubical box

${\sf{\pink{\underline{\Large{Explanation}}}}}$

Diagram

$\setlength{\unitlength}{5mm}\begin{picture}(5,5)\multiput(0,0)(0,6){2}{\multiput(0,0)(2,1){2}{\line(1,0){12}}\multiput(0,0)(12,0){2}{\line(2,1){2}}}\multiput(0,0)(12,0){2}{\multiput(0,0)(2,1){2}{\line(0,1){6}}}\end{picture}$

We know that

Volume of cube = a³

• Here volume is given =110.592m³

According to the question

=>a³ = 110.592m³

$= \sqrt[3]{ \frac{110592}{1000} } \\ = \frac{48}{10} \\ = 4.8$

Hence value of a is 4.8

Additional Information

Tsa = 6a²

Csa = 4a²

Answer 2

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$\huge{\bold{\star{\fcolorbox{black}{red}{Question...}}}}$

• ✏Find the "Edge" of a "Cubical Box", if its volume is $\sf\large{110.592\:m^{3}}$✍

______________________________

$\huge{\bold{\fcolorbox{black}{lime}{Answer...}}}$

$\bold{\red{\underline{\underline{Given:-}}}}$

• ✏Volume of the "Cubical Box"= $\sf\large\green{110.592m^{3}}$✍

$\bold{\purple{\underline{\underline{To\:Find:-}}}}$

• ✏"Edge" of the Cubical Box.✍

$\large{\underline{\underline{\mathbb{\orange{A.T.Q.(According\:To\:Question)}}}}}$

$\sf\large{\red{\implies{Volume\:of\:Cube= Edge × Edge × Edge}}}$

$\sf\large{\purple{\implies{110.592\:m^{3} = Edge^{3}}}}$

$\sf\large{\orange{\implies{\sqrt[3]{110.592\:m^{3}}= Edge}}}$

$\sf\large{\red{\implies{4.8\:m = Edge}}}$

$\bold{\red{\underline{\underline{Therefore,}}}}$

$\sf\large{\green{Length \:of\:Edge\:of\:Cube= 4.8\:meter \:or\: 480\:centimeter....}}$

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