Question

find the effective resistance of the circuit when two resistance of 4ohm and 12ohm are connected
a) in series
b) parallel

Answer 1

$\red{HEY\:MISS!!}$

HERE'S THE ANSWER..

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♠️ Case 1

✔️ $\underline{In\: Series}$

⏺️ R 1 = 4 ohm

⏺️R 2 = 12 ohm

▶️ Effect resistance [ R ] in series is sum of individual resistance connect end to end ( series )

=> $\boxed{R\: = R1 \: + \:R2}$

=> R = 12 ohm + 4 ohm

=> R = 16 Ohm

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♠️ Case 2

✔️ $\underline{In\: Parallel}$

▶️Effect resistance [ R ] in Parallel is sum of reciprocal of individual resistance connected in Parallel

=> $\boxed{1 \: / \:R\: = 1\: / \: R1 \: +1 \: / \:R2}$

=> 1 / R = 1 / 12 + 1 / 4

=> 1 / R = 4 / 12

=> 1 / R = 1 / 3

=> R = 3 Ohm

♠️ Alway take care in series resistance will be more as compare to that in parallel.

HOPE HELPED..

$\blue{JAI \:HIND}$

:)

Answer 2

Heya!!

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In Series :

Effective resistance = sum of individual resistance

Req = 4 ohm + 12 ohm

= 16 ohm.

In parallel :

Reciprocal of effective resistance = sum of reciprocal of individual resistance

1/Req = 1/4 + 1/12

=) 1/Req = 4/12

=) Req = 12/4

= 3 ohm.

Hope it helps uh!!