find the effective resistance
r1=3ohm
r2=3ohm
r3=3ohm
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If we take any two of the resistances,they'll be in series.
So, R1 + R2 = Rs
Rs = 3 + 3 = 6 ohm
Rs and bc are in parallel.
So, 1/R1 + 1/R2 = 1/Rp
1/6 + 1/3 = 1/Rp
》Rp = 1/2 ohm
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Answered by
1
Answer:
1/R parallel= 1/3+1/3=2/3
R total= 3+ 3/2
= 9/2
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