Find the efficiency of a Carnot engine if the temperature of the source if 100 c and sink is 27 c
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Answer:
127 degrees
Explanation:
Taking the Sink Temperature(T2) = 27 degree celsius = 300 kelvin
Efficiency(eta) be 25% = .25
Source Temperature(T1) = ?
Efficiency= (T1 - T2) / T1
Efficiency= 1 -T2/T1
T2/T1 = 1 - Efficiency
T1 = T2/(1 - Efficiency)
T1= 300/(1-.25)
T1 = 400 kelvin = 127 degree celsius
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