Question

Find the efficiency of the carnot's engine working between 150°C and 50°C

plzzzz solve this​

Answer 1

Answer:-

$\eta = 0.2$

Explanation:-

$T_1 : \blue{\texttt{Temperature\: of \:source}}$

$T_2 : \blue{\texttt{Temperature\: of\: sink}}$

Given:

• $T_1 = 150 \degree C = 423k$
• $T_2 = 50 \degree C = 323k$

To Find:

Efficiency ($\eta$) of carnot engine.

Solution:-

W.k.t,

$\boxed{\bold{\green{\eta = 1 - \dfrac{T_2}{T_1}}}}$

$\eta = 1 - \dfrac{323}{423}$

$\eta = \dfrac{423-323}{423}$

$\eta =\dfrac{100}{423}$

$\bold {\eta = 0.2}$

Answer 2

Th= 150° =273+150= 423 K

Tc= 50° = 323 K

efficiency (n) = 423/323 = 1.309