Find the electric current in the following circuit. (Ans : 0.1A),Solve the given example.
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From the figure we can see that the 2 resistors are connected in series and the other is in parallel with the others two.
∴ For Series,
Rs = 30 + 30 = 60 Ω
For Parallel,
1/Rp = 1/Rs + 1/R
⇒ 1/Rp = 1/60 + 1/30
∴ 1/Rp = 3/60
⇒ Rp = 20 Ω
Now, Potential = 2 V
Using the Formula,
V = I × Rp
⇒ 2 = I × 20
⇒ I = 2/20
∴ I = 0.1 A
Hence, the current flowing through the conductor is 0.1 A.
Hope it helps.
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