Question

Find the electric field intensity of a point charge 2uc at a distance of 10 cm in air.​

Answer 1

Explanation:

Let the charge is placed at distance x from 2μc

Now the net force acting on charge q should be zero.

⇒ (10−x)2k(1×10−6)q=x2(2×10−6)q

⇒10−x1=x2

⇒x=102−x2

⇒x(1+2)=102

⇒x=1+2102

⇒x=2.41414.14

⇒x=5.857cm