Question

Find the electric intensity at a point where a charge 5*10-⁴ coulomb. experience of a force is 2.25 Newton

Answer 1

Given ,

• Charge (q) = 5 × (10)^(-4) C
• Force (f) = 2.25 Newton

We know that , the electric field intensity is defined as the force experienced by a unit charge

Mathematically ,

$\boxed{ \tt{Electric \: field \: intensity \: (E) = \frac{f}{q} }}$

Thus ,

E = 2.25 / 5 × 10^(-4)

E = 0.45 × (10)^4

E = 4.5 × (10)^(3) N/c

Therefore , the electric field intensity is 4.5 × (10)^(3) N/c

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