Question

Find the electric potential at a point if 0.002joule work is done to bring a 40mc charge from infinity to that point

Answer 1

Answer:

given, work done,W =0.002 joule

and a charge q=40 mC=40*10^-3 C

now, work done=charge*electric potential

=electric potential=W/q

=0.002/40*10^-3= 0.05 joules/coulomb

Answer 2

Answer:5volt

Explanation:

Electric potential=V volt =?

Given that;

Work done(W) =0.002joule

and charge(Q)= 40microC = 40×10^_5C

Now,since

Electric potential =workdone(joule)/charges(coulomb)

Therefore

V=W/Q

or V=0.002/40×10^-5

Or V=2×10^5/40×1000

Or V=10/2

Or V=5joule/coulomb answer