find the electric potential at point p due to electric dipole separated by a distance 2a
-q-------o-------+q-----------p
distance between o and p = r
Answers
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Answer:
The dipole moment, p=q×2a
We will calculate potential at any point P, where
OP=r and ∠BOP=θ
Let BP=r
1
and AP=r
2
Draw AC perpendicular PQ and BD perpendicular PO
In ΔAOC cosθ=OC/OA=OC/a
OC=acosθ
Similarly, OD=acosθ
Potential at P due to +q=
4πϵ
0
1
r
2
q
And Potential at P due to −q=
4πϵ
0
1
r
1
q
Net potential at P due to the dipole
V=
4πϵ
0
1
(
r
2
q
−
r
1
q
)
⟹V=
4πϵ
0
q
(
r
2
1
−
r
1
1
)
Now, r
1
=AP=CP
=OP+OC
=r+acosθ
And r
2
=BP=DP
=OP–OD
=r−acosθ
V=
4πϵ
0
q
(
r−acosθ
1
−
r+acosθ
1
)
=
4πϵ
0
q
(
r
2
−a
2
cos
2
θ
2acosθ
)
=
r
2
−a
2
cos
2
θ
pcosθ
(Since p=2aq)
Special cases:-
(i) When the point P lies on the axial line of the dipole, θ=0
∘
cosθ=1
V=
r
2
−a
2
p
If a<<r, V=
r
2
p
Thus due to an electric dipole ,potential, V∝
r
2
1
(ii) When the point P lies on the equatorial line of the dipole, θ=90
∘
cosθ=0
i.e electric potential due to an electric